If R1 = 2 Ω and R2 = 10 Ω are connected in series, what is the total resistance?

Unlock all questions

This demo includes only 20 questions. Upgrade to access hundreds of questions, flashcards, exam simulations, and disable ads.

Full question bankExam simulationsFlashcards
From $9.99Unlock all

Study for the DC Theory LMS Test. Engage with comprehensive flashcards and interactive multiple choice questions, each equipped with helpful hints and clear explanations. Prepare confidently and efficiently for your exam!

Multiple Choice

If R1 = 2 Ω and R2 = 10 Ω are connected in series, what is the total resistance?

Explanation:
When resistors are in series, the same current flows through each component, so their resistances simply add. Total resistance = R1 + R2. Here that’s 2 Ω + 10 Ω = 12 Ω. In series, the opposition to current is the sum of all resistances, which is why you add them directly. (In case you’re curious, if these were in parallel, you’d use the reciprocal rule 1/R = 1/2 + 1/10.) The essential point is that series resistances add to give the total.

When resistors are in series, the same current flows through each component, so their resistances simply add. Total resistance = R1 + R2. Here that’s 2 Ω + 10 Ω = 12 Ω. In series, the opposition to current is the sum of all resistances, which is why you add them directly. (In case you’re curious, if these were in parallel, you’d use the reciprocal rule 1/R = 1/2 + 1/10.) The essential point is that series resistances add to give the total.

More Multiple Choice Questions
Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy